Private Sub Command1_ Click( )
Dim a(1 To 6) As Long，i As Integer
a(1)=1
a(2)= 1
For i=3 To 6
a(i)=a(i-1)+2 * a(i- 2)
Next i
Text1. Text=Str(a(6))
Text2. Text= Str(i)
End Sub
def f(m, n):
q=m%n
if q == 0:
return n
else:
return f(n,q)
print(f(14,10))
F(1)=3
F(n)=F(n-1)*2
n=int(input())
f0,f1,f2=1,0,1
for i in range(3,n+1):
▲
f0,f1,f2= f1,f2,f3
print("爬n级台阶的方案数为",f3)
则划线处的代码为。该段代码使用了 (填：递归或迭代)算法。
def fibs(n):
if n==1 or n==2:
return ____①____
return _____②_____
m=int(input("请输入一个整数："))
for i in range(1,m+1):
print(___③___ ,end=",")
def f(n):
if n == 5:
return ___①___
return _____②____
print(___③___)
a(1)=1：a(2)=1
b(1)=1：b(2)=2
For i=3 To 5
a(i)=a(i-1)+a(i-2)
b(i)=b(i-1)+a(i)
执行该程序段后，数组元素b(5)的值为（ ）