import pandas as pd

import matplotlib.pyplot as plt

df = pd.read_excel("浙江 A 级景区.xlsx")

df = df.drop(["电话", "景区编码"],  )  # 删除不必要的列

for row in range(len(df)):  # 整理“等级”列数据

    grade = df.at[row, "等级"]

    if '1' <= grade[0] <= '9':

        df.at[row, "等级"] = "A" * int(grade[0])

df2 = df[ >= "AAAA"]

dfg = df2.groupby("地市").count()

dfg = dfg.rename(columns={'等级': "数量"})   # 重命名列名称

dfg. ("数量", ascending=False, inplace=True)

plt.figure(figsize=(8,4))

plt.rcParams['font.sans-serif']=['SimHei','FangSong']

plt.title("浙江 AAAA 级以上景区数量统计图")

for i in range(len(dfg)):

    plt.text(i, dfg["数量"][i]+1, dfg["数量"][i])

plt.xlabel("地市名称")

plt.ylabel("数量")

plt.legend( )

plt.show ( )

为实现上述功能，则加框处的语句最合适的是(    )  (单选，填字母)

def qj(l,r,a):        #将二进制 a 转成对应的经纬度范围#该代码省略

def find(c):        #在 base32 表中查找对应的十进制数

    for i in :

        if base32[i]==c:

            return i base32="0123456789bcdefghjkmnpqrstuvwxyz" s=input("请输入编码：")

res="" jd=[]

wd=[]

for i in range(len(s)):

    ans=""

    j=0

    while:

        ans=

        n=n//2

        j+=1

    res=res+ans

for i in range(len(res)):

    if i%2==0:

        jd+=res[i]

    else:

        wd+=res[i]

print("经度对应的二进制:",jd,"纬度对应的二进制:",wd)

print("经度范围：",qj(-180,180,jd),"纬度范围：",qj(-90,90,wd))